200=6x^2-40x

Solution for 200=6x^2-40x equation:

200=6x^2-40x

We move all terms to the left:

200-(6x^2-40x)=0

We get rid of parentheses

-6x^2+40x+200=0

a = -6; b = 40; c = +200;
Δ = b2-4ac
Δ = 402-4·(-6)·200
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-80}{2*-6}=\frac{-120}{-12}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+80}{2*-6}=\frac{40}{-12}
=-3+1/3
$